Calculate the volume occupied at s.t.p by 6.89 gas [H = 10, N = 14​

Question

Calculate the volume occupied
at s.t.p by 6.89
gas [H = 10, N = 14​

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Diễm Kiều 2 months 2021-07-28T17:07:17+00:00 1 Answers 4 views 0

Answers ( )

    0
    2021-07-28T17:08:30+00:00

    Answer:

    9.07 L

    Explanation:

    Calculate the volume occupied at s.t.p by 6.89 g of NH₃ gas [H = 1.0, N = 14.0​].

    Step 1: Given and required data

    • Mass of NH₃ (m): 6.89 g
    • Molar mass of NH₃ (M): 17.0 g/mol

    Step 2: Calculate the moles (n) of NH₃

    We will use the following epxression.

    n = m / M

    n = 6.89 g / (17.0 g/mol) = 0.405 mol

    Step 3: Calculate the volume occupied by 0.405 moles of NH₃ at STP

    At STP, 1 mole of NH₃ occupies 22.4 L (assuming ideal behavior).

    0.405 mol × 22.4 L/1 mol = 9.07 L

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