Calculate the volume, in milliliters, for the following: .850 mol of NaNO3, from a .500 M NaNO3 solution 30.0 g of L

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Question

Calculate the volume, in milliliters, for the following:

.850 mol of NaNO3, from a .500 M NaNO3 solution

30.0 g of LiOH from a 2.70 M LiOH solution

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Chemistry Thiên Hương 4 years 2021-08-23T23:03:32+00:00 2021-08-23T23:03:32+00:00 1 Answers 11 views 0

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hongcuc2 · Answer 1 · 2021-08-23T23:05:23+00:00

Answer: The volume for 0.850 mol of $NaNO_{3}$ from a $NaNO_{3}$ solution is 1700 mL.

The volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

Explanation:

Molarity is the number of moles of solute present in a liter of solution.

As given moles of $NaNO_{3}$ are 0.850 mol and molarity of $NaNO_{3}$ solution is 0.5 M. Hence, its volume is calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\0.5 M = \frac{0.850 mol}{Volume}\\Volume = 1.7 L (1 L = 1000 mL)\\= 1700 mL$

Therefore, the volume for 0.850 mol of $NaNO_{3}$ from a $NaNO_{3}$ solution is 1700 mL.

As given mass of LiOH are 30.0 g from a 2.70 M LiOH (molar mass = 23.95 g/mol) solution. Hence, its number of moles are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{30.0 g}{23.95 g/mol}\\= 1.25 mol$

So, volume for LiOH solution is calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\2.70 M = \frac{1.25}{Volume}\\Volume = 0.464 L (1 L = 1000 mL)\\= 464 mL$

Therefore, volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.