Calculate the volume 3.00 moles of a gas will occupy at 24.0°C and 105.2 kPa, 140. L 35.4L 15.4L 70.4L<

Question

Calculate the volume 3.00 moles of a gas will occupy at 24.0°C and 105.2
kPa,
140. L
35.4L
15.4L
70.4L

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Xavia 2 months 2021-07-31T19:39:22+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-07-31T19:41:05+00:00

    Answer:

    70.34 litres

    Explanation:

    Using ideal gas law equation;

    PV = nRT

    Where;

    P = pressure (atm)

    V = volume (L)

    n = number of moles (mol)

    R = gas law constant (0.0821 Latm/molK)

    T = temperature (K)

    According to the information given in the question;

    n = 3 moles

    V = ?

    P = 105.2 KPa = 105.2/101 = 1.04atm

    T = 24.0°C = 24 + 273 = 297K

    Using PV = nRT

    1.04 × V = 3 × 0.0821 × 297

    1.04V = 73.15

    V = 73.15 ÷ 1.04

    V = 70.34 litres.

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