Calculate the tension in a horizontal leather string that whirls a 0.5-kg rock in a circle of radius 1.25 m when it moves at 8 m/s while bei

Question

Calculate the tension in a horizontal leather string that whirls a 0.5-kg rock in a circle of radius 1.25 m when it moves at 8 m/s while being slung around a slinger’s head.

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Helga 5 years 2021-08-18T03:14:10+00:00 1 Answers 13 views 0

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  1. Euphemia
    0
    2021-08-18T03:15:56+00:00
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    Answer:

    Tension in the leather string is T = 25.6 N

    Explanation:

    As we know that belt is revolving in horizontal circle

    So the tension force in the belt will provide the required centripetal force

    So we will have

    T = \frac{mv^2}{L}

    now we have

    v = 8 m/s

    L = 1.25 m

    m = 0.5 kg

    so we have

    T = \frac{0.5(8^2)}{1.25}

    T = 25.6 N

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