Calculate the number of moles of NaOH in an aqueous solution of 36 cm3 of 0.1 mol dm−3. PLSS EXPLAIN WHAT YOU DO I DONT GET IT

Question

Calculate the number of moles of NaOH in an aqueous solution of 36 cm3 of 0.1 mol dm−3.
PLSS EXPLAIN WHAT YOU DO I DONT GET IT

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Sapo 5 years 2021-07-14T19:30:10+00:00 1 Answers 12 views 0

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  1. lethu
    0
    2021-07-14T19:31:31+00:00
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    Answer: The number of moles of NaOH is 0.0036 moles

    Explanation:

    Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

    \text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{ \text{Volume of solution (mL)}} …..(1)

    Given values:

    Molarity of NaOH = 0.1mol/dm^3=0.1mol/L         (Conversion factor: 1L=1dm^3

    Volume of the solution = 36cm^3=36 mL             (Conversion factor: 1mL=1cm^3

    Putting values in equation 1, we get:

    0.1=\frac{\text{Moles of NaOH}\times 1000}{36}\\\\\text{Moles of NaOH}=\frac{0.1\times 36}{1000}=0.0036mol

    Hence, the number of moles of NaOH is 0.0036 moles

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