Calculate the molarity of 29.25 grams of NaCI in 2.0 liters of solution

Question

Calculate the molarity of 29.25 grams of NaCI in 2.0 liters of solution

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Dulcie 7 months 2021-07-11T14:22:57+00:00 1 Answers 9 views 0

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    2021-07-11T14:24:32+00:00

    Answer:

    [NaCl(aq)] = 0.25M

    Explanation:

    Molarity = moles solute / volume of solution in liters

    moles NaCl in 29.25 grams = 29.25g/58g·mol⁻¹ = 0.5043 mole

    Molarity = 0.5043 mole NaCl / 2 Liters = 0.2555M ≅ 0.25M (2 sig-figs)

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