Calculate the molar mass of Ca3(PO4)2 934.32 g Ca3(PO4)2 =______ moles Ca3(PO4)2

Question

Calculate the molar mass of Ca3(PO4)2

934.32 g Ca3(PO4)2 =______
moles Ca3(PO4)2

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Ngọc Diệp 4 years 2021-07-30T16:15:26+00:00 1 Answers 6 views 0

Answers ( )

  1. hongcuc2
    0
    2021-07-30T16:16:49+00:00
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    Answer:

    • Molar mass of Ca₃(PO₄)₂ = 310.18 g/mol
    • 934.32 g Ca₃(PO₄)₂ = 3.01 moles Ca₃(PO₄)₂

    Explanation:

    The molar mass (MM) of Ca₃(PO₄)₂ can be calculated as follows:

    • MM of Ca₃(PO₄)₂ = (MM of Ca)*3 + [(MM of P) +(MM of O)*4]*2
    • MM of Ca₃(PO₄)₂ = 310.18 g/mol

    Now we can convert 934.32 g of Ca₃(PO₄)₂ into moles:

    • 934.32 g ÷ 310.18 g/mol = 3.01 moles

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