Calculate the kinetic energy of a 790-kg roller coaster traveling at a velocity of 20.7 m/s.

Question

Question

in progress 0

Physics King 4 years 2021-08-14T21:23:01+00:00 2021-08-14T21:23:01+00:00 2 Answers 65 views 0

Answers ( )

Name*

E-Mail*

Website

Featured image

Browse

Captcha* Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )

Answer*

Amity · Answer 1 · 2021-08-14T21:24:30+00:00

Answer:

$\displaystyle KE = 169254 \ J$

General Formulas and Concepts:

Energy

Kinetic Energy Formula: $\displaystyle KE = \frac{1}{2}mv^2$

Explanation:

Step 1: Define

[Given] m = 790 kg

[Given] v = 20.7 m/s

Step 2: Solve

Substitute in variables [Kinetic Energy Formula]: $\displaystyle KE = \frac{1}{2}(790 \ kg)(20.7 \ m/s)^2$
[KE] Evaluate exponents: $\displaystyle KE = \frac{1}{2}(790 \ kg)(428.49 \ m^2/s^2)$
[KE] Multiply: $\displaystyle KE = (395 \ kg)(428.49 \ m^2/s^2)$
[KE] Multiply: $\displaystyle KE = 169254 \ J$

kimchi2 · Answer 2 · 2021-08-14T21:24:39+00:00

kimchi2

0

2021-08-14T21:24:39+00:00 August 14, 2021 at 9:24 pm

Reply

Answer:

The answer is 169253.55 joules