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Calculate the electric force between two point charges of -54.0 μC and +36.0 μC when they are 2.00 cm apart. **note — the metr
Question
Calculate the electric force between two point charges of -54.0 μC and +36.0 μC when they are 2.00 cm apart.
**note — the metric prefix “micro” = μ = x10 – 6 **
Is this attractive or repulsive?
Can someone help me please? Thank you!!!!
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Physics
4 years
2021-08-01T05:12:28+00:00
2021-08-01T05:12:28+00:00 1 Answers
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Answers ( )
Answer:
43740 N and attractive force
Explanation:
Given that,
Charge 1, q₁ = -54.0 μC
Charge 2, q₂ = +36.0 μC
The distance between charges, r = 2 cm = 0.02 m
We need to find the force between charges. The formula for the force between charges is given by :
Put all the values,
As the charges are opposite, the force between them is attractive. Hence, the required force is 43740 N.