Calculate the angular momentum of a 2 kg cylinder pulley with radius 0.1 m that rotates at a constant angular speed of 2 rad/s.

Question

Calculate the angular momentum of a 2 kg cylinder pulley with radius 0.1 m that rotates at a constant angular speed of 2 rad/s.

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RI SƠ 1 year 2021-07-18T11:03:28+00:00 1 Answers 68 views 0

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    2021-07-18T11:05:17+00:00

    Answer:

    The angular momentum of cylinder pulley is [tex]0.02 \ kg\ m^2\ rad /s\\[/tex] .

    Explanation:

    Given :

    Mass of pulley , m = 2 kg .

    Radius of pulley , R = 0.1 m .

    Angular velocity of pulley , [tex]\omega=2\ rad/s[/tex] .

    We need to find the angular momentum

    We know , angular momentum of a rigid body is given by :

    [tex]L=I\omega[/tex]       ……( 1 )

    Here , I is the angular momentum of cylindrical pulley and is given by :

    [tex]I=\dfrac{MR^2}{2}\\\\I=\dfrac{2\times 0.1^2}{2}\\\\I=0.01\ kg \ m^2[/tex]

    Putting value of I and [tex]\omega[/tex] in equation 1 .

    We get :

    [tex]L=0.01\times 2\ kg\ m^2\ rad /s\\\\L=0.02 \ kg\ m^2\ rad /s\\[/tex]

    Therefore , the angular momentum of cylinder pulley is [tex]0.02 \ kg\ m^2\ rad /s\\[/tex] .

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