## Calculate the angular momentum of a 2 kg cylinder pulley with radius 0.1 m that rotates at a constant angular speed of 2 rad/s.

Question

Calculate the angular momentum of a 2 kg cylinder pulley with radius 0.1 m that rotates at a constant angular speed of 2 rad/s.

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1 year 2021-07-18T11:03:28+00:00 1 Answers 68 views 0

The angular momentum of cylinder pulley is $$0.02 \ kg\ m^2\ rad /s\\$$ .

Explanation:

Given :

Mass of pulley , m = 2 kg .

Radius of pulley , R = 0.1 m .

Angular velocity of pulley , $$\omega=2\ rad/s$$ .

We need to find the angular momentum

We know , angular momentum of a rigid body is given by :

$$L=I\omega$$       ……( 1 )

Here , I is the angular momentum of cylindrical pulley and is given by :

$$I=\dfrac{MR^2}{2}\\\\I=\dfrac{2\times 0.1^2}{2}\\\\I=0.01\ kg \ m^2$$

Putting value of I and $$\omega$$ in equation 1 .

We get :

$$L=0.01\times 2\ kg\ m^2\ rad /s\\\\L=0.02 \ kg\ m^2\ rad /s\\$$

Therefore , the angular momentum of cylinder pulley is $$0.02 \ kg\ m^2\ rad /s\\$$ .