Calculate the angular momentum of a 2 kg cylinder pulley with radius 0.1 m that rotates at a constant angular speed of 2 rad/s.

Question

Calculate the angular momentum of a 2 kg cylinder pulley with radius 0.1 m that rotates at a constant angular speed of 2 rad/s.

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RI SƠ 6 months 2021-07-18T11:03:28+00:00 1 Answers 33 views 0

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    2021-07-18T11:05:17+00:00

    Answer:

    The angular momentum of cylinder pulley is 0.02 \ kg\ m^2\ rad /s\\ .

    Explanation:

    Given :

    Mass of pulley , m = 2 kg .

    Radius of pulley , R = 0.1 m .

    Angular velocity of pulley , \omega=2\ rad/s .

    We need to find the angular momentum

    We know , angular momentum of a rigid body is given by :

    L=I\omega       ……( 1 )

    Here , I is the angular momentum of cylindrical pulley and is given by :

    I=\dfrac{MR^2}{2}\\\\I=\dfrac{2\times 0.1^2}{2}\\\\I=0.01\ kg \ m^2

    Putting value of I and \omega in equation 1 .

    We get :

    L=0.01\times 2\ kg\ m^2\ rad /s\\\\L=0.02 \ kg\ m^2\ rad /s\\

    Therefore , the angular momentum of cylinder pulley is 0.02 \ kg\ m^2\ rad /s\\ .

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