Calculate the amount of heat energy required to heat up 15.9 grams of ice from -4 °C to 14°C.

Question

Calculate the amount of heat energy required to heat up 15.9 grams of ice from -4 °C to 14°C.

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Dulcie 1 year 2021-08-31T02:03:47+00:00 1 Answers 4 views 0

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    2021-08-31T02:05:36+00:00

    Answer:

    581 Joules.

    Explanation:

    Using the formula;

    Q = m × c × ∆T

    Where;

    Q = amount of heat absorbed (J)

    m = mass of substance (g)

    c = specific heat capacity (J/g°C)

    ∆T = change in temperature (°C)

    According to the information provided in this question;

    Q = ?

    mass of ice = 15.9g

    initial temperature = -4°C

    final temperature = 14°C

    Hence, ∆T = 14 – (-4) = 14 + 4 = 18°C

    specific heat capacity (c) of ice in J/g°C = 2.03 J/g°C

    Using Q = m × c × ∆T

    Q = 15.9 × 2.03 × 18

    Q = 32 × 18

    Q = 581 Joules.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )