Calculate how fast the ball would be moving at the instant it leaves the projectile launcher of the spring is compressed by 3.75 cm. Use a v

Question

Calculate how fast the ball would be moving at the instant it leaves the projectile launcher of the spring is compressed by 3.75 cm. Use a value of k = 500 N/m for the spring constant, 10 g for the mass of the ball, and 75 g for the effective mass of the ball holder. Show your work.

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Ben Gia 1 week 2021-07-21T20:43:13+00:00 1 Answers 4 views 0

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    2021-07-21T20:44:38+00:00

    Answer:

    V = 8.34m/s

    Explanation:

    Given that

    1/2ke^2 = 1/2mv^2 ……1

    Where e = 3.75cm = (3.75/100)m

    e = 0.0375m

    K = 500 N/m

    m = 10g = 10/1000

    = 0.01kg

    Substitute the values into equation 1

    0.5×500×(0.0375)^2 = 0.5×0.01×v^2

    250×0.001395 = 0.005v^2

    0.348 = 0.005v^2

    v^2 = 0.348/0.005

    v^2 = 69.6

    V = √69.6

    V = 8.34m/s

    The ball launches at the speed of V = 8.34m/s

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