Calcular la cantidad de NaOH necesaria para preparar medio litro de disolución 2,5 N. (Dato: peso molecular del NaOH = 40 g/mol).

Question

Calcular la cantidad de NaOH necesaria para preparar medio litro de disolución 2,5 N. (Dato: peso molecular del NaOH = 40 g/mol).

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Latifah 18 mins 2021-07-22T19:47:25+00:00 1 Answers 0 views 0

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    2021-07-22T19:49:01+00:00

    Answer:

    The amount of NaOH required to prepare a solution of 2.5N NaOH.

    The molecular mass of NaOH is 40.0g/mol.

    Explanation:

    Since,

    NaOH has only one replaceable -OH group.

    So, its acidity is one.

    Hence,

    The molecular mass of NaOH =its equivalent mass

    Normality formula can be written as:Normality=\frac{mass of solute NaOH}{its equivalent mass}  * \frac{1}{volume of solution in L} \\

    Substitute the given values in this formula to get the mass of NaOH required.

    2.5N=\frac{mass of NaOH}{40g/mol} *\frac{1}{1L} \\mass of NaOH=2.5N*40gmol\\                         =      100.0g

    Hence, the mass of NaOH required to prepare 2.5N and 1L. solution is 100g

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