C2 = 20.0 μF, and C3 = 25.0 μF. If no capacitor can withstand a potential difference of more than 100 V without failure, what are (a) the ma

Question

C2 = 20.0 μF, and C3 = 25.0 μF. If no capacitor can withstand a potential difference of more than 100 V without failure, what are (a) the magnitude of the maximum potential difference that can exist between points A and B and (b) the maximum energy that can be stored in the three-capacitor arrangement?

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Thu Thủy 1 week 2021-09-04T17:56:09+00:00 1 Answers 0 views 0

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    2021-09-04T17:57:31+00:00

    Answer:

    A) 300 V

    B) 44,447J

    Explanation:

    A) from the question, the capacitors are in series.

    Therefore, the total potential between points A and B would be the sum total of potentials across each of the capacitors.

    So, Maximum potential across A and B = [100 + 100 + 100]V = 300V

    B) Let Cs be the effective capacitance of the series combination;

    So, 1/Cs = (1/10) + (1/20) +(1/25)

    1/Cs = 0.1 + 0.05 + 0.04

    1/Cs = 0.19

    Cs = 1/0.19 = 5.26 microF

    Energy stored = (1/2) Cs(V)^(2)

    = (1/2) x 5.26 x (130^(2)) = 44,447J

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