Block A of mass M is on a horizontal surface of negligible friction. An identical block B is attached to block A by a light string that pass

Question

Block A of mass M is on a horizontal surface of negligible friction. An identical block B is attached to block A by a light string that passes over an ideal pulley. The tension force exerted on block A after the system is released from rest has magnitude T. Block B is then replaced by a block of mass 2M and the system again released from rest.
Which of the following is a correct expression for the tension force now exerted on block A?

a) 12T b) 23T c) 34T d) 43T e) 2T

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MichaelMet 1 year 2021-07-24T19:03:29+00:00 1 Answers 348 views 0

Answers ( )

    1
    2021-07-24T19:05:25+00:00

    Answer:

    T’= 4/3 T  

    The new tension is 4/3 = 1.33 of the previous tension the answer e

    Explanation:

    For this problem let’s use Newton’s second law applied to each body

    Body A

    X axis

          T = m_A a

    Axis y

         N- W_A = 0

    Body B

    Vertical axis

         W_B – T = m_B a

    In the reference system we have selected the direction to the right as positive, therefore the downward movement is also positive. The acceleration of the two bodies must be the same so that the rope cannot tension

    We write the equations

        T = m_A a

        W_B –T = M_B a

    We solve this system of equations

         m_B g = (m_A + m_B) a

        a = m_B / (m_A + m_B) g

    In this initial case

         m_A = M

         m_B = M

         a = M / (1 + 1) M g

         a = ½ g

    Let’s find the tension

        T = m_A a

        T = M ½ g

        T = ½ M g

    Now we change the mass of the second block

        m_B = 2M

        a = 2M / (1 + 2) M g

        a = 2/3 g

    We seek tension for this case

        T’= m_A a

        T’= M 2/3 g

       

    Let’s look for the relationship between the tensions of the two cases

       T’/ T = 2/3 M g / (½ M g)

       T’/ T = 4/3

       T’= 4/3 T

    The new tension is 4/3 = 1.33 of the previous tension the answer  e

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