Biologists have studied the running ability of the northern quoll, a marsupial indigenous to Australia. In one set of experiments, they stud

Question

Biologists have studied the running ability of the northern quoll, a marsupial indigenous to Australia. In one set of experiments, they studied the maximum speed that quolls could run around a curved path without slipping. One quoll was running at 2.4 m/sm/s around a curve with a radius of 1.4 mm when it started to slip. What was the coefficient of static friction between the quoll’s feet and the ground in this trial?

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Sapo 6 months 2021-08-02T21:00:10+00:00 1 Answers 21 views 0

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    2021-08-02T21:01:38+00:00

    Answer:

    Explanation:

    velocity of quoll  v = 2.4 m/s

    radius of circular path R = 1.4  m .

    The centripetal force in its circular motion will be provided by friction force which will act towards the center

    centripetal acceleration = v² / R

    = 2.4 x 2.4 / 1.4

    = 4.11  m/s²

    force = mass x acceleration

    friction force =  m x 4.11   , where m is mass of quoll

    Normal force N = mg

    coefficient of friction = friction force / normal force

    = m x 4.11  / m x 9.8

    = .42 Ans

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