Bài 5 : tìm x,biết a) ( x – `(1)/(2)` ) ^4 – 3 . 5 = (-65)^0 November 16, 2020 by Euphemia Bài 5 : tìm x,biết a) ( x – `(1)/(2)` ) ^4 – 3 . 5 = (-65)^0
`(x-1/2)^4-3.5=(-65)^0` `=>(x-1/2)^4-15=1` `=> (x-1/2)^4=1+15=16` `=> (x-1/2)^4=±2^4` `=> x-1/2 = 2` hoặc `x-1/2=-2` `=> x=5/2` hoặc `x=-3/2` Reply
`(x-1/2)^4-3.5=(-65)^0` `(x-1/2)^4-15=1` `(x-1/2)^4=16` \(↔\left[ \begin{array}{l}x-\dfrac{1}{2}=2\\x-\dfrac{1}{2}=-2\end{array} \right.\) \(↔\left[ \begin{array}{l}x=\dfrac{5}{2}\\x=-\dfrac{3}{2}\end{array} \right.\) Vậy `x={5/2,-3/2}` Reply
`(x-1/2)^4-3.5=(-65)^0`
`=>(x-1/2)^4-15=1`
`=> (x-1/2)^4=1+15=16`
`=> (x-1/2)^4=±2^4`
`=> x-1/2 = 2` hoặc `x-1/2=-2`
`=> x=5/2` hoặc `x=-3/2`
`(x-1/2)^4-3.5=(-65)^0`
`(x-1/2)^4-15=1`
`(x-1/2)^4=16`
\(↔\left[ \begin{array}{l}x-\dfrac{1}{2}=2\\x-\dfrac{1}{2}=-2\end{array} \right.\)
\(↔\left[ \begin{array}{l}x=\dfrac{5}{2}\\x=-\dfrac{3}{2}\end{array} \right.\)
Vậy `x={5/2,-3/2}`