Bài 1 tìm xen a (2x-1(x-1)=0 b,(3x-1)(x-4)=0 Bài 2 so sánh A=234.234 B=233.235 giúp mình với nhé October 31, 2020 by Ben Gia Bài 1 tìm xen a (2x-1(x-1)=0 b,(3x-1)(x-4)=0 Bài 2 so sánh A=234.234 B=233.235 giúp mình với nhé
Giải thích các bước giải: Bài 1a)`(2x-1)(x-1)=0``=>`\(\left[ \begin{array}{l}2x-1=0\\x-1=0\end{array} \right.\) `=>`\(\left[ \begin{array}{l}2x=0+1\\x=0+1\end{array} \right.\) `=>`\(\left[ \begin{array}{l}2x=1\\x=1\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x=1:2\\x=1\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x=\dfrac{1}{2}\\x=1\end{array} \right.\) `Vì x∈N` `=>x∈{1}`b)`(3x-1)(x-4)=0``=>`\(\left[ \begin{array}{l}3x-1=0\\x-4=0\end{array} \right.\) `=>`\(\left[ \begin{array}{l}3x=0+1\\x=0+4\end{array} \right.\)`=>`\(\left[ \begin{array}{l}3x=1\\x=4\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x=1:3\\x=4\end{array} \right.\)`=>`\(\left[ \begin{array}{l}x=\dfrac{1}{3}\\x=4\end{array} \right.\) `Vì x∈N``=>x∈{4}`Bài 2 So sánh`A=234.234``A=54756``B=233.235``B=54755`` Vì ` `54756>54755``=>A>B` Reply
Đáp án:
Giải thích các bước giải:
Giải thích các bước giải:
Bài 1
a)
`(2x-1)(x-1)=0`
`=>`\(\left[ \begin{array}{l}2x-1=0\\x-1=0\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}2x=0+1\\x=0+1\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}2x=1\\x=1\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=1:2\\x=1\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=\dfrac{1}{2}\\x=1\end{array} \right.\)
`Vì x∈N`
`=>x∈{1}`
b)
`(3x-1)(x-4)=0`
`=>`\(\left[ \begin{array}{l}3x-1=0\\x-4=0\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}3x=0+1\\x=0+4\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}3x=1\\x=4\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=1:3\\x=4\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=\dfrac{1}{3}\\x=4\end{array} \right.\)
`Vì x∈N`
`=>x∈{4}`
Bài 2 So sánh
`A=234.234`
`A=54756`
`B=233.235`
`B=54755`
` Vì ` `54756>54755`
`=>A>B`