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Atmospheric conditions near the Gulf of Mexico are such that a cloud at an altitude of 1.90 km contains 3.20 ✕ 107 kg of water vapor. How lo
Question
Atmospheric conditions near the Gulf of Mexico are such that a cloud at an altitude of 1.90 km contains 3.20 ✕ 107 kg of water vapor. How long (in years) would it take for a 2.21 kW pump to raise this amount of water (at a constant speed) from Earth’s surface to the altitude of the cloud?
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2021-08-18T02:04:39+00:00
2021-08-18T02:04:39+00:00 1 Answers
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Answer:
t = 8.55 years
Explanation:
The formula for power is given as:
Power = Work/Time
but, the work here is equal to the increase in potential energy of the water. Therefore,
Power = P.E/Time
P = mgh/t
t = mgh/P
where,
t = time required = ?
P = Power of pump = 2.21 KW = 2210 W
m = mass of water = 3.2 x 10⁷ kg
h = height = 1.9 km = 1900 m
g = 9.8 m/s²
Therefore,
t = (3.2 x 10⁷ kg)(9.8 m/s²)(1900 m)/(2210 W)
t = (2.69 x 10⁸ s)(1 h/3600 s)(1 day/24 h)(1 year/365 days)
t = 8.55 years