At the top of a giant swing on the high bar, a 50 kg gymnast’s velocity is 3 m/s, and he is 3.5 m high. What is the gymnast’s total mechanic

Question

At the top of a giant swing on the high bar, a 50 kg gymnast’s velocity is 3 m/s, and he is 3.5 m high. What is the gymnast’s total mechanical energy (KE + PE+ SE) at this instant?

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Phúc Điền 2 months 2021-08-30T20:50:55+00:00 1 Answers 5 views 0

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    2021-08-30T20:52:23+00:00

    Answer:

    Total Mechanical Energy of the gymnast = 1940J = 1.94 kJ

    Explanation:

    Total Mechanical Energy = KE + PE + SE

    Kinetic Energy, KE = 1/2 MV^{2}

    KE = 0.5 * 50 * 3^{2} \\KE = 225 J

    Potential Energy,

    PE = mgh\\PE = 50 * 9.8 * 3.5\\\\PE=1715 J

    Strain Energy,

    SE = 1/2 K x^{2}

    Since there is no force of deformation, x = 0, SE = 0

    Total Mechanical Energy = 225 + 1715

    Total Mechanical Energy of the gymnast = 1940J = 1.94 kJ

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