At the local playground, a 16-kg child sits on the end of a horizontal teeter-totter, 1.5 m from the pivot point. On the other side of the p

Question

At the local playground, a 16-kg child sits on the end of a horizontal teeter-totter, 1.5 m from the pivot point. On the other side of the pivot an adult pushes straight down on the teeter-totter with a force of 95 N. In which direction does the teeter-totter rotate if the adult applies the force at a distance of (a) 3.0 m, (b) 2.5 m, or (c) 2.0 m from the pivot

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Khải Quang 6 months 2021-07-27T03:30:25+00:00 1 Answers 12 views 0

Answers ( )

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    2021-07-27T03:32:09+00:00

    Answer:

    Explanation:

    a ) the weight of child creates a torque equal to = mg x L where m is mass of the child , L is distance from pivot

    = 16 x 9.8 x 1.5

    = 235.2 Nm

    force applied by man  F = 95 N , distance from pivot = 3 m

    torque = force x distance from pivot

    95 x 3 = 285 Nm which is greater than the torque produced by child so

    teeter-totter will tilt towards adult person

    b ) in this case distance of force from pivot = 2.5

    torque produced by it

    = 95 x 2.5

    = 237.5 Nm , this too is more . So this time too,  teeter-totter will tilt towards adult person

    c ) in this case distance of force from pivot = 2.0

    torque produced by it

    = 95 x 2.0

    = 190 Nm

    which is less than the torque produced by child so

    teeter-totter will tilt towards child .  

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