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At the local playground, a 16-kg child sits on the end of a horizontal teeter-totter, 1.5 m from the pivot point. On the other side of the p
Question
At the local playground, a 16-kg child sits on the end of a horizontal teeter-totter, 1.5 m from the pivot point. On the other side of the pivot an adult pushes straight down on the teeter-totter with a force of 95 N. In which direction does the teeter-totter rotate if the adult applies the force at a distance of (a) 3.0 m, (b) 2.5 m, or (c) 2.0 m from the pivot
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Physics
6 months
2021-07-27T03:30:25+00:00
2021-07-27T03:30:25+00:00 1 Answers
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Answers ( )
Answer:
Explanation:
a ) the weight of child creates a torque equal to = mg x L where m is mass of the child , L is distance from pivot
= 16 x 9.8 x 1.5
= 235.2 Nm
force applied by man F = 95 N , distance from pivot = 3 m
torque = force x distance from pivot
95 x 3 = 285 Nm which is greater than the torque produced by child so
teeter-totter will tilt towards adult person
b ) in this case distance of force from pivot = 2.5
torque produced by it
= 95 x 2.5
= 237.5 Nm , this too is more . So this time too, teeter-totter will tilt towards adult person
c ) in this case distance of force from pivot = 2.0
torque produced by it
= 95 x 2.0
= 190 Nm
which is less than the torque produced by child so
teeter-totter will tilt towards child .