At the equator, near the surface of the Earth, the magnetic field is approximately 50.0 μT northward, and the electric field is about 100 N/

Question

At the equator, near the surface of the Earth, the magnetic field is approximately 50.0 μT northward, and the electric field is about 100 N/C downward in fair weather. Find the gravitational, electric, and magnetic forces on an electron in this environment, assuming that the electron has an instantaneous velocity of 8.50 ✕ 106 m/s directed to the east.

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Hải Đăng 3 months 2021-08-17T01:54:31+00:00 1 Answers 15 views 0

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    2021-08-17T01:56:25+00:00

    Answer:

    A) F_g = 8.9278 × 10^(-30)

    B) F_e = 1.6 × 10^(-17) N upwards

    C) F_m = 6.8 × 10^(-17) N downwards

    Explanation:

    A) Formula for gravitational force is;

    F_g = m_e × g

    m_e is mass of electron = 9.11 x 10^(-31) kg

    F_g = 9.11 x 10^(-31) × 9.8

    F_g = 8.9278 × 10^(-30) N downwards

    B) Formula for Electric force is;

    F_e = qe

    q is charge on electron = 1.6 × 10^(-19) C

    E is electric field = 100 N/C

    F_e = 1.6 × 10^(-19) × 100

    F_e = 1.6 × 10^(-17) N upwards

    C) Magnetic force is given by the formula;

    F_m = qVB

    q is charge on electron = 1.6 × 10^(-19) C

    V is velocity given as 8.50 × 10^(6) m/s

    B is magnetic field = 50.0 μT = 50 × 10^(-6) T

    F_m = 1.6 × 10^(-19) × 8.50 × 10^(6) × 50 × 10^(-6)

    F_m = 6.8 × 10^(-17) N downwards

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