At the end of 3N force acts on the object during time interval of 1.5seconds with force acting towards right. A constant force of 4N to left

Question

At the end of 3N force acts on the object during time interval of 1.5seconds with force acting towards right. A constant force of 4N to left is applied for 3seconds. What is the velocity at the end of the 3seconds ?

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Thiên Hương 6 months 2021-08-10T14:36:10+00:00 1 Answers 3 views 0

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    2021-08-10T14:37:16+00:00

    Answer:

    v_f = -7.5 m / s

    Explanation:

    Let’s analyze this exercise a little, two forces that act on a body for different time intervals are indicated, each force creates an impulse and since this is a vector quantity we must add in the form of vectors. The net momentum is

    we assume that the direction to the right is positive

                 I = I₁ + I₂

                 I = F₁ Δt₁ – F₂ Δt₂

                 I = 3  1.5 – 4  3

                 I = -7.5   N s

    now let’s use the relationship between momentum and momentum, suppose the object starts from rest (vo = 0)

                 I = Δp

                 I = m (v_f – v₀)

                 

                 v_f = I / m

                 

                  v_f = -7.5 / m

    to finish the calculation we must assume a mass m = 1 kg

                  v_f = -7.5 m / s

    the negative sign in the body is moving to the left

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