At STP, what is the volume of 55.0 g of BF3?

Question

At STP, what is the volume of 55.0 g of BF3?

in progress 0
Euphemia 2 months 2021-07-23T16:41:27+00:00 1 Answers 5 views 0

Answers ( )

    0
    2021-07-23T16:42:46+00:00

    Answer:

    The volume of 55 grams of BF₃ is 18.1664 L.

    Explanation:

    If the molar mass of compound BF₃ is 67.81 \frac{grams}{mole}, then the number of moles 55 grams of compound contains is calculated as:

    55 grams* \frac{1 mole}{67.81 grams} = 0.811 moles

    The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

    Then it is possible to apply the following rule of three: if by definition of STP 1 mole of a compound occupies 22.4 L, 0.811 moles of the compound occupies how much volume?

    volume=\frac{0.811 moles* 22.4 L}{1 mole}

    volume= 18.1664 L

    The volume of 55 grams of BF₃ is 18.1664 L.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )