At a pressure of one atmosphere oxygen boils at −182.9°C and freezes at −218.3°C. Consider a temperature scale where the boiling point of ox

Question

At a pressure of one atmosphere oxygen boils at −182.9°C and freezes at −218.3°C. Consider a temperature scale where the boiling point of oxygen is 100.0°O and the freezing point is 0°O. Determine the temperature on the Oxygen scale that corresponds to the absolute zero point on the Kelvin scale.

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Thu Hương 3 years 2021-08-22T14:00:14+00:00 1 Answers 19 views 0

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    2021-08-22T14:01:32+00:00

    Answer: -254.51°O

    Explanation:

    Ok, in our scale, we have:

    -182.9°C corresponds to 100° O

    -218.3°C corresponds to 0°

    Then we can find the slope of this relation as:

    S = (100° – 0°)/(-182.9°C – (-218.3°C)) = 2.82°O/°C

    So we can have the linear relationship between the scales is:

    Y = (2.82°O/°C)*X + B

    in this relation, X is the temperature in Celcius and Y is the temperature in the new scale.

    And we know that when X = -182.9°C, we must have Y = 0°O

    then:

    0 = (2.82°O/°C)*(-182.9°C) + B

    B = ( 2.82°O/°C*189.9°C) = 515.778°O.

    now, we want to find the 0 K in this scale, and we know that:

    0 K = -273.15°C

    So we can use X =  -273.15°C in our previous equation and get:

    Y = (2.82°O/°C)*(-273.15°C) + 515.778°O = -254.51°O

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