At a certain temperature, 0.700 mol SO3 is placed in a 3.50 L container. 2SO3(g)↽−−⇀2SO2(g)+O2(g) At equilibrium, 0.180 mol O2 is present. C

Question

At a certain temperature, 0.700 mol SO3 is placed in a 3.50 L container. 2SO3(g)↽−−⇀2SO2(g)+O2(g) At equilibrium, 0.180 mol O2 is present. Calculate c.

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Thu Giang 4 years 2021-07-26T08:57:53+00:00 1 Answers 15 views 0

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  1. dangkhoa
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    2021-07-26T08:59:16+00:00
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    Answer: The value of K_c for the given chemical equation is 0.0457.

    Explanation:

    Given values:

    Initial moles of SO_3 = 0.700 moles

    Volume of conatiner = 3.50 L

    The given chemical equation follows:

                2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)

    I:             0.700

    C:              -2x           +2x           x

    E:           0.700-2x      2x            x

    Equilibrium moles of O_2 = x = 0.180 moles

    Equilibrium moles of SO_2 = 2x = (2\times 0.180)=0.360moles

    Equilibrium moles of SO_3 = 0.700 – 2x = 0.700-(2\times 0.180)=0.340moles

    Molarity is calculated by using the equation:

    Molarity=\frac{Moles}{Volume}

    So,

    [SO_3]_{eq}=\frac{0.340}{3.50}=0.0971M

    [SO_2]_{eq}=\frac{0.360}{3.50}=0.103M

    [O_2]_{eq}=\frac{0.180}{3.50}=0.0514M

    The expression of K_c for above equation follows:

    K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}

    Plugging values in above expression:

    K_c=\frac{(0.0971)^2\times 0.0514}{(0.103)^2}\\\\K_c=0.0457

    Hence, the value of K_c for the given chemical equation is 0.0457.

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