At 304 K, a 9.6 L tank contains 1.9 moles of H2 gas under an unknown pressure in atm. What is the pressure of the gas in the tank? (R = 0.08

Question

At 304 K, a 9.6 L tank contains 1.9 moles of H2 gas under an unknown pressure in atm. What is the pressure of the gas in the tank? (R = 0.0821 L*atm/mol*K)

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Thu Nguyệt 4 years 2021-08-11T07:19:54+00:00 2 Answers 37 views 0

Answers ( )

  1. quangkhai
    0
    2021-08-11T07:21:50+00:00
    Reply

    Answer:

    4.9 atm

    Explanation:

  2. Tryphena
    1
    2021-08-11T07:21:51+00:00
    Reply

    Answer:

    The pressure is 4.939 atm

    Explanation:

    As we know

    PV = nRT

    where P is the pressure

    V is the volume

    n is the total number of moles

    R is the gas constant

    and T is the temperature

    Substituting the given values we get –

    P * 9.6 = 1.9 * 0.0821 *304\\P = 47.420/9.6\\P = 4.939

    The pressure is 4.939 atm

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