At 300.0 K and 0.987 atm pressure, what will be the volume of 2.30 mol of Ne?

Question

At 300.0 K and 0.987 atm pressure, what will be the volume of 2.30 mol of Ne?

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Nem 3 years 2021-07-31T04:38:56+00:00 1 Answers 6 views 0

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  1. thuhuong
    0
    2021-07-31T04:40:35+00:00
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    Answer:

    V = 57.39 L

    Explanation:

    Given that,

    Temperature, T = 300 K

    Pressure, P = 0.987 atm

    No. of moles of Ne, n = 2.30 mol

    We need to find the volume of Ne. We know that, the ideal gas law is as follows :

    PV = nRT

    Where

    P is pressure and R is gas constant

    V=\dfrac{nRT}{P}\\\\V=\dfrac{2.3\times 0.0821\times 300}{0.987 }\\\\V=57.39\ L

    So, the volume of the Ne is 57.39 L.

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