(Assume there is no friction) A bike starts rolling down a hill at 4.3 m/s . After 12 s it reaches the bottom moving at 11.5 m/s. How long

Question

(Assume there is no friction) A bike starts rolling down a hill at 4.3 m/s . After 12 s it reaches the bottom moving at 11.5 m/s. How long was the hill? Express your answer with the correct number of significant digits.

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Ngọc Khuê 5 months 2021-08-22T07:25:15+00:00 1 Answers 8 views 0

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    2021-08-22T07:27:06+00:00

    Answer:

    d = 94.8 \ m

    Explanation:

    Given data:

    Initial velocity, u = 4.3 \ m/s

    Final velocity, v = 11.5 \ m/s

    Time, t = 12 \ s

    The acceleration of the bike can be expressed as,

    a = \frac{v-u}{t}

    a = \frac{11.5-4.3}{12}

    a = 0.6 \ m/s^{2}.

    The distance of the hill can be given as,

    d = ut + \frac{1}{2}at^{2}

    d = 4.3 \times 12 + 0.5 \times 0.6 \times (12)^{2}

    d = 94.8 \ m.

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