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Assume a reaction takes 7.5 moles of anhydrous calcium chloride and energy transfer occurs, which we record as 21.2 joules of energy. Find t
Question
Assume a reaction takes 7.5 moles of anhydrous calcium chloride and energy transfer occurs, which we record as 21.2 joules of energy. Find the heat of solution in J/mol and round to two places after the decimal point.
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2021-07-27T11:19:00+00:00
2021-07-27T11:19:00+00:00 2 Answers
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Answers ( )
Answer:
Heat of solution; ΔH = 2.83 J/mol
Explanation:
We are given;
Number of moles; n = 7.5 moles
Energy absorbed; q = 21.2 J
Now, in endothermic reactions,
ΔH = q/n
Where ;
ΔH is heat of solution
q is amount of energy absorbed
n is number of moles of solute
Thus, plugging in relevant values, we have;
ΔH = q/n
ΔH = 21.2/7.5
ΔH = 2.83 J/mol
Answer: 2.83 J/mol
Explanation:
Heat of solution, sometimes interchangeably called enthalpy of solution, is said to be the energy released or absorbed when the solute dissolves in the solvent. A solute is that which can dissolve in a solvent, to form a solution
Given
No of moles of CaCl = 7.5 mol
Total energy used = 21.2 J
Heat of solution = q/n where
q = total energy
n = number of moles
Heat of solution = 21.2 / 7.5
Heat of solution = 2.83 J/mol