Assume a reaction takes 7.5 moles of anhydrous calcium chloride and energy transfer occurs, which we record as 21.2 joules of energy. Find t

Question

Assume a reaction takes 7.5 moles of anhydrous calcium chloride and energy transfer occurs, which we record as 21.2 joules of energy. Find the heat of solution in J/mol and round to two places after the decimal point.

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Thu Thủy 6 months 2021-07-27T11:19:00+00:00 2 Answers 7 views 0

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    0
    2021-07-27T11:20:23+00:00

    Answer:

    Heat of solution; ΔH = 2.83 J/mol

    Explanation:

    We are given;

    Number of moles; n = 7.5 moles

    Energy absorbed; q = 21.2 J

    Now, in endothermic reactions,

    ΔH = q/n

    Where ;

    ΔH is heat of solution

    q is amount of energy absorbed

    n is number of moles of solute

    Thus, plugging in relevant values, we have;

    ΔH = q/n

    ΔH = 21.2/7.5

    ΔH = 2.83 J/mol

    0
    2021-07-27T11:20:23+00:00

    Answer: 2.83 J/mol

    Explanation:

    Heat of solution, sometimes interchangeably called enthalpy of solution, is said to be the energy released or absorbed when the solute dissolves in the solvent. A solute is that which can dissolve in a solvent, to form a solution

    Given

    No of moles of CaCl = 7.5 mol

    Total energy used = 21.2 J

    Heat of solution = q/n where

    q = total energy

    n = number of moles

    Heat of solution = 21.2 / 7.5

    Heat of solution = 2.83 J/mol

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