Ask Your Teacher A piece of wire is bent through an angle θ. The bent wire is partially submerged in carbon disulfide (index of refraction n

Question

Ask Your Teacher A piece of wire is bent through an angle θ. The bent wire is partially submerged in carbon disulfide (index of refraction n = 1.628) so that, to a person looking along the dry part, the wire appears to be straight and makes an angle of 26.4° with the horizontal. Determine the value of θ.

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Vodka 3 years 2021-07-29T09:49:16+00:00 1 Answers 17 views 0

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  1. Doris
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    2021-07-29T09:50:50+00:00
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    Answer:

    θ1 = 33.38°

    Explanation:

    From Snell’s law of refraction,

    n1•sinθ1 = n2•sinθ2

    We are given ;

    Angle of refraction; θ2 = (90 – 26.4°) = 63.6°

    Index of refraction; n1 = 1.628

    Index of refraction in air; n2 will have a constant value of 1

    Now, we are looking for angle of incidence θ1, so let’s make θ1 the subject;

    n1•sinθ1 = n2•sinθ2

    So, sinθ1 = (n2•sinθ2)/n1

    Plugging in the relevant values;

    sinθ1 = (1 x sin 63.6)/1.628

    sinθ1 = 0.5502

    θ1 = sin^(-1)0.5502

    θ1 = 33.38°

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