Ask Your Teacher A beam of light is incident from air on the surface of a liquid. If the angle of incidence is 33.5° and the angle of refrac

Question

Ask Your Teacher A beam of light is incident from air on the surface of a liquid. If the angle of incidence is 33.5° and the angle of refraction is 19.3°, find the critical angle for the liquid when surrounded by air.

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Edana Edana 2 months 2021-07-26T17:50:16+00:00 1 Answers 1 views 0

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    2021-07-26T17:51:34+00:00

    Answer:

    The critical angle for the liquid when surrounded by air is 30 degrees.      

    Explanation:

    Given that,

    The angle of incidence is 33.5° and the angle of refraction is 19.3°. Firstly, we can find the refractive index of the liquid. It can be calculated using Snell’s law as :

    n=\dfrac{\sin i}{\sin r}\\\\n=\dfrac{\sin (33.5)}{\sin (19.3)}\\\\n=2

    The critical angle is given by :

    \theta_c=\sin^{-1}(\dfrac{n_1}{n_2})

    Here, n_1 is refractive index of air and n_2 is refractive index of liquid.

    \theta_c=\sin^{-1}(\dfrac{1}{2})\\\\\theta_c=30^{\circ}

    So, the critical angle for the liquid when surrounded by air is 30 degrees.

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