Ask Your Teacher A basketball player shoots toward a basket 5.8 m away and 3.0 m above the floor. If the ball is released 1.7 m above the fl

Question

Ask Your Teacher A basketball player shoots toward a basket 5.8 m away and 3.0 m above the floor. If the ball is released 1.7 m above the floor at an angle of 60° above the horizontal, what must the initial speed be (in m/s) if it were to go through the basket?

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Thái Dương 4 years 2021-09-05T06:01:11+00:00 1 Answers 8 views 0

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  1. Farah
    0
    2021-09-05T06:02:24+00:00
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    Answer:

    The answer to your question is    vo = 5.43 m/s

    Explanation:

    Data

    distance = d= 5.8 m

    height = 3 m

    height 2 = 1.7 m

    angle = 60°

    vo = ?

    g = 9.81 m/s²

    Formula

                  hmax = vo²sinФ/ 2g

    Solve for vo²

                  vo² = 2ghmax / sinФ

    Substitution

                  vo² = 2(9.81)(3 – 1.7) / 0.866

    Simplification

                  vo² = 19.62(1.3) / 0.866

                  vo² = 25.51 / 0.866

                  vo² = 29.45

    Result

                  vo = 5.43 m/s

                   

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