Aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce a precipitate of copper (II) phosphate and aqueous potas

Question

Aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce
a precipitate of copper (II) phosphate and aqueous potassium sulfate.

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MichaelMet 3 years 2021-09-02T07:12:43+00:00 1 Answers 21 views 0

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  1. thaiduong
    0
    2021-09-02T07:13:52+00:00
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    Answer:

    CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄

    Explanation:

    The question is missing but I think it must be about writing and balancing the equation.

    Let’s consider the unbalanced equation for the reaction that occurs when aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce  a precipitate of copper (II) fluoride (I fixed a mistake here) and aqueous potassium sulfate. This is a double displacement reaction.

    CuSO₄(aq) + KF(aq) = CuF₂ + K₂SO₄

    Since only K and F atoms are not balanced, we will get the balanced equation by multiplying KF by 2.

    CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )