Andrew goes to the shop to buy some apples and bananas. He goes to purchase 5 apples and 4 bananas, and the total comes to $ 5.70

Question

Andrew goes to the shop to buy some apples and bananas.

He goes to purchase 5 apples and 4 bananas, and the total comes to $ 5.70.

Unfortunality, he doesn’t have enough money, so he puts back 1 apple and 2

bananas.

The new total is $ 3.60. What is the cost of 1 apple and the cost of 1 banana?

b. Andrea’s budget is $6. If she buys equal number of apples and bananas, then

what is the maximum number of apples and bananas, she can buy?

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Nho 2 days 2021-07-22T14:23:06+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-22T14:24:38+00:00

    Answer:

    a. The price of an apple is $0.5 and that of a banana is $0.8

    b. 4

    Step-by-step explanation:

    Form simultaneous equations from the information.

    For 5 apples and 4 bananas, and the total comes to $ 5.70 this can be;

    5 a + 4 b = $5.70———-i

    After he puts back 1 apple and 2  bananas, the equation will be;

    4 a + 2 b = $3.60 ————-ii

    Solve the two equations simultaneously as;

    {5 a + 4 b = 5.70 }4 ———making the a terms equal to eliminate them

    {4 a + 2 b = 3.60}5

    20 a + 16 b = 22.80 ——-subtract the b terms

    20 a  + 10b = 18.00

    6 b = 4.80

    b= 4.80/ 6

    b=$ 0.8

    Using equation i :

    5a + 4b =$5.70

    5a + 4*0.8 = 5.70

    5a + 3.2 = 5.70

    5a = 2.5

    a = 2.5 / 5

    a=$0.5

    The price of an apple is $0.5 and that of a banana is $0.8

    b.  

    Let the number of apples be ——x

    Let the number of bananas be—–x

    This is because the target is equal numbers;

    Form an equation for total cost as;

    0.5 x + 0.8 x = $6

    1.3 x = 6

    x = 1.3 / 6 = 4.62

    Maximum number of bananas to buy = 4

    Maximum number of apples to buy = 4

    However, he will have $0.8 remaining

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