An urn has 21 balls that are identical except that 8 are white, 7 are red, and 6 are blue. What is the probability that all are white if 3 a

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An urn has 21 balls that are identical except that 8 are white, 7 are red, and 6 are blue. What is the probability that all are white if 3 are selected randomly without replacement?

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Trúc Chi 3 years 2021-07-28T05:36:33+00:00 1 Answers 14 views 0

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    2021-07-28T05:37:37+00:00

    Answer:

    .0421

    about 4.21%

    Step-by-step explanation:

    \frac{{8\choose3}}{{21\choose3}}=\frac{56}{1330}=.042105263

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