An unusual lightning strike has a vertical portion with a current of –400 A downwards. The Earth’s magnetic field at that location is parall

Question

An unusual lightning strike has a vertical portion with a current of –400 A downwards. The Earth’s magnetic field at that location is parallel to the ground and has a magnitude of 30 μT. In units of N (Newtons), the force exerted by the Earth’s magnetic field on the 25 m-long current is Group of answer choices 300 A, East. 0.30 A, West. 0 0.012 A, East. 0.012 A, West.

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Kim Chi 7 months 2021-07-17T10:11:36+00:00 1 Answers 27 views 0

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    2021-07-17T10:12:36+00:00

    Given that,

    Current, I = 400 A (downwards)

    The Earth’s magnetic field at that location is parallel to the ground and has a magnitude of 30 μT.

    We need to find the force exerted by the Earth’s magnetic field on the 25 m-long current. We know that the magnetic force is given by :

    F=iLB\sin\theta

    Here, \theta=90^{\circ}

    F=400\times 25\times 30\times 10^{-6}\\\\F=0.3\ N

    The force is acting in a plane perpendicular to the current and the magnetic field i.e out of the plane.

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