An unpolarized light with an intensity of 20W/m^2 is passed through a pair of polarizers. The first polarizer is set at an angle of 60° and

Question

An unpolarized light with an intensity of 20W/m^2 is passed through a pair of polarizers. The first polarizer is set at an angle of 60° and the second is set at an angle of 20°. Using Malus’ law, what is the intensity of light as it passes through the second polarizer?

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Acacia 3 years 2021-07-29T19:22:39+00:00 1 Answers 6 views 0

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    2021-07-29T19:24:38+00:00

    Answer:

    4.416 W/m²

    Explanation:

    Malus’ law is given mathematically as

    I = I₀ cos² θ

    For the first polarizer, θ = 60°

    I₁ = I₀ cos² 60°

    I₁ = I₀ (0.5)² = 0.25I₀

    For the second polarizer, θ = 20°

    I₂ = I₁ cos² 20°

    I₂ = I₁ (0.9397)² = 0.883 I₁

    I₂ = 0.883 × 0.25I₀ = 0.2208 I₀

    Note that

    I₀ = 20 W/m²

    I₂ = 0.2208 × 20 = 4.416 W/m²

    Hope this Helps!!!

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