An unknown substance weighing 42.0 g was heated from 36.0°C to 65.0°C. In this process, the substance absorbed 5895 J of energy

Question

An unknown substance weighing 42.0 g was heated from 36.0°C to 65.0°C. In this process, the
substance absorbed 5895 J of energy. What is the specific heat of the substance?

A. 5895 J/(g*C)
B. 4.18 J/(g*C)
C. 4.84 J/( g*C)
D. O.06 J/(g*C)

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Helga 3 months 2021-07-26T01:51:34+00:00 1 Answers 4 views 0

Answers ( )

    0
    2021-07-26T01:53:01+00:00

    Answer:

    A. 5895 J/g*C)

    Explanation:

    An unknown substance weighing 42.0 g was heated from 36.0°C to 65.0°C. In this process, the substance absorbed 5895 J of energy.

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