An unknown piece of metal absorbs 1350 J of heat as 55.0 g of the metal heats up from 20.0 oC to 47.0 oC

Question

An unknown piece of metal absorbs 1350 J of heat as 55.0 g of the metal heats up from 20.0 oC to 47.0 oC

in progress 0
Thiên Ân 4 years 2021-09-03T12:59:05+00:00 1 Answers 3 views 0

Answers ( )

  1. ngochoa
    0
    2021-09-03T13:00:57+00:00
    Reply

    Answer:

    C=0.91\frac{J}{g\°C}

    Explanation:

    Hello there!

    In this case, according to the given information, it is possible to recall the equation to calculate the heat, Q, in these calorimetry problems as shown below:

    Q=mC(T_f-T_i)

    Thus, given the absorbed heat, mass and temperatures, we can easily calculate the specific heat of the metal as shown below:

    C=\frac{Q}{m(T_f-T_i)}

    Then, by plugging in we obtain:

    C=\frac{1350J}{55.0g(47.0\°C-20.0\°C)} \\\\C=0.91\frac{J}{g\°C}

    Best regards!

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )