An unknown organic compound composed of carbon, hydrogen and oxygen was analyzed and found to be 50.84% C, 8.53% H and the rest being oxygen

Question

An unknown organic compound composed of carbon, hydrogen and oxygen was analyzed and found to be 50.84% C, 8.53% H and the rest being oxygen. Which of the following represents the correct empirical formula for the compound?
(a) CH2O
(b) C3H602
(c) C4H803
(d) C2H40
(e) C5H1003

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Trúc Chi 6 months 2021-07-17T11:55:45+00:00 1 Answers 149 views 0

Answers ( )

    0
    2021-07-17T11:57:44+00:00

    Answer:

    e) C5H10O3

    Explanation:

    According to the information given in this question;

    50.84% represents C

    8.53% represents H

    [100% – (50.84 + 8.53)]

    = 100 – 59.37

    = 40.63% of Oxygen (O)

    This percentage means that;

    Carbon = 50.84g

    Hydrogen = 8.53g

    Oxygen = 40.63g

    By dividing by their respective atomic masses, we convert to moles:

    C = 50.84g ÷ 12 = 4.24mol

    H = 8.53g ÷ 1 = 8.53mol

    O = 40.63g ÷ 16 = 2.54mol

    Next we divide by the smallest no of the values (2.54mol)

    C = 4.24 ÷ 2.54 = 1.669

    H = 8.53 ÷ 2.54 = 3.358

    O = 2.54 ÷ 2.54 = 1

    To get a simple whole number ratio, we multiply the results by 3

    C = 1.669 × 3 = 5.007

    H = 3.358 × 3 = 10.074

    O = 1 × 3 = 3

    Simple whole number ratio of carbon, hydrogen and oxygen is 5:10:3. Hence, the empirical formula is C5H10O3.

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