An x-ray beam of a certain wavelength is incident on a crystal, at 30.7° to a certain family of reflecting planes of spacing 33.4 pm. If the

An x-ray beam of a certain wavelength is incident on a crystal, at 30.7° to a certain family of reflecting planes of spacing 33.4 pm. If the reflection from those planes is of the first order, what is the wavelength of the x rays?

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  1. Answer:

    The wavelength of the x rays is 34.104 pm

    Explanation:

    Given data:

    θ = incidence angle = 30.7°

    d = space between planes = 33.4 pm = 33.4 x10⁻¹²m

    According Bragg’s expression:

    [tex]n\lambda =2dsin\theta \\n=1,first-order\\\lambda = 2dsin\theta\\\lambda =2*33.4*sin30.7=34.104pm[/tex]

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  2. Answer:

    λ=34.068pm

    Explanation:

    Wavelength λ=2dsinθ

    λ=2(33.4pm)sin30.7

    λ=2(33.4pm) * 0.510

    λ=66.8* sin30.7

    λ=66.8*0.510

    λ=34.068pm

    X-rays are usually produced by charged particles that are accelerating or decelerating such as a beam of electrons striking a metal plate in an X-ray tube.

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