An open container contained 150g of lead carbonate. After heating for 5 hours, the contents of the container were measured to have a mass of

Question

An open container contained 150g of lead carbonate. After heating for 5 hours, the contents of the container were measured to have a mass of 98g.
How much mass was “lost” from the container? Where did it go?

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Thu Hương 5 months 2021-08-16T04:48:29+00:00 1 Answers 2 views 0

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    2021-08-16T04:49:38+00:00

    Answer:

    52 g was lost as carbon dioxide to the atmosphere

    Explanation:

    When lead carbonate is heated, it decomposes into two components:

    1. Lead oxide

    2. carbon dioxide

    While the lead oxide remains a yellow solid in the heating container, the carbon dioxide escapes into the atmosphere as a gas. The equation of the reaction is as below:

    PbCO_3_{(s)} --> PbO_{(s)} + CO_2_{(g)}

    Hence, if a 150 g lead oxide is heated in a container and the final mass is 98 g, it means 52 g (150 – 98) of the total mass has been lost as carbon dioxide to the atmosphere.

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