An Olympic diver is on a diving platform 10.1 m above the water. To start her dive, she runs off of the platform with a speed of 1.28 m/s in

Question

An Olympic diver is on a diving platform 10.1 m above the water. To start her dive, she runs off of the platform with a speed of 1.28 m/s in the horizontal direction. What is the diver’s speed, in m/s, just before she enters the water?

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Euphemia 3 months 2021-07-22T00:46:27+00:00 1 Answers 0 views 0

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    2021-07-22T00:47:48+00:00

    Answer:

    v = 14.13 m/s

    Explanation:

    We are given;

    Height of platform above water; S_y = 10.1m

    Horizontal component of velocity; V_x = 1.28 m/s

    First of all, let’s find time taken for the displacement.

    t = √[(2S_y)/g]

    t = √[(2 x 10.1)/9.8]

    t = √[(20.2)/9.8]

    t = 1.436 s

    Let’s use Newton’s equation of motion for vertical component of velocity;

    (v_y) = u + gt

    (v_y) = 0 + (9. 8 x 1.436)

    (v_y) = 14.07 m/s

    So, final speed is the resultant of v_x and v_y.

    So;

    v = √((v_x)² + (v_y)²)

    v = √((1.28)² + (14.07)²)

    v = √199.6033

    v = 14.13 m/s

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