An observer standing near a window 5 m high observe that an object falling downwards is passing across the window in 0.5 s. Find at what hei

Question

An observer standing near a window 5 m high observe that an object falling downwards is passing across the window in 0.5 s. Find at what height above the window the object was dropped. (g = 10 m/s2).​

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Acacia 2 months 2021-07-23T06:11:42+00:00 1 Answers 67 views 0

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    2021-07-23T06:13:03+00:00

    Answer:

    Explanation:

    An object in free fall, NOT experiencing parabolic motion, has an equation of

    h(t)=\frac{1}{2} gt^2+h_0 which says:

    The height of an object with respect to time in seconds is equal to the pull of gravity times time-squared plus the height from which it was dropped. Normally we use -9.8 for gravity but you said to use 10, so be it.

    For us, h(t) is 5 because we are looking for the height of the window when the object is 5 m off the ground at .5 seconds;

    g = 10 m/s/s, and

    t = .5sec

    5=\frac{1}{2}(-10)(.5)^2+h and

    5 = -5(.5)² + h and

    5 = -5(.25) + h and

    5 = -1.25 + h so

    h = 6.25

    That’s how high the window is above the ground.

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