an object weights 0.250 kgf in air 0.150 in water and 0.125 in an oil.find out the density of the object and the oil​

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1. Answer:

   1) The density of the object = 2500 kg/m³

   2) The density of the oil = 1250 kg/m³

   Explanation:

   1) The information relating to the question are;

   The mass of the object in air = 0.250 kgf

   The mass of the object in water = 0.150 kgf

   The mass of the object in the oil  = 0.125 kgf

   By Archimedes’s principle, we have;

   The upthrust on the object in water = Mass in air – mass in water = The weight of the water displaced

   The upthrust on the object in water = 0.250 – 0.150 = 0.1 kgf

   ∴ The weight of the water displaced = 0.1 kgf

   Given that the object is completely immersed in the water, we have;

   The volume of the water displaced = The volume of the object

   The volume of 0.1 kg of water water displaced = Mass of the water/(Density of water)

   The volume of 0.1 kg of water = 0.1/1000 = 0.0001 m³

   The density of the object = (Mass in air)/ volume = 0.250/0.0001 = 2500 kg/m³

   The density of the object = 2500 kg/m³

   2) Whereby the mass of the object in the oil = 0.125 kgf

   The upthrust of the oil = The weight of the oil displaced

   The upthrust of the oil on the object = Mass of the object in air – mass of the object in the oil

   The upthrust of the oil on the object = 0.250 – 0.125 = 0.125 kgf

   The weight of the oil displaced = The upthrust of the oil

   Given that the volume of the oil displaced = The volume of the oil, we have;

   The volume of the oil displaced = 0.0001 m³

   The mass of the 0.0001 m³ = 0.125 kg

   Therefore the density of the oil = 0.125/0.0001 = 1250 kg/m³.

   The density of the oil = 1250 kg/m³.

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