an object weights 0.250 kgf in air 0.150 in water and 0.125 in an oil.find out the density of the object and the oil August 11, 2021 by Delwyn an object weights 0.250 kgf in air 0.150 in water and 0.125 in an oil.find out the density of the object and the oil
Answer: 1) The density of the object = 2500 kg/m³ 2) The density of the oil = 1250 kg/m³ Explanation: 1) The information relating to the question are; The mass of the object in air = 0.250 kgf The mass of the object in water = 0.150 kgf The mass of the object in the oil = 0.125 kgf By Archimedes’s principle, we have; The upthrust on the object in water = Mass in air – mass in water = The weight of the water displaced The upthrust on the object in water = 0.250 – 0.150 = 0.1 kgf ∴ The weight of the water displaced = 0.1 kgf Given that the object is completely immersed in the water, we have; The volume of the water displaced = The volume of the object The volume of 0.1 kg of water water displaced = Mass of the water/(Density of water) The volume of 0.1 kg of water = 0.1/1000 = 0.0001 m³ The density of the object = (Mass in air)/ volume = 0.250/0.0001 = 2500 kg/m³ The density of the object = 2500 kg/m³ 2) Whereby the mass of the object in the oil = 0.125 kgf The upthrust of the oil = The weight of the oil displaced The upthrust of the oil on the object = Mass of the object in air – mass of the object in the oil The upthrust of the oil on the object = 0.250 – 0.125 = 0.125 kgf The weight of the oil displaced = The upthrust of the oil Given that the volume of the oil displaced = The volume of the oil, we have; The volume of the oil displaced = 0.0001 m³ The mass of the 0.0001 m³ = 0.125 kg Therefore the density of the oil = 0.125/0.0001 = 1250 kg/m³. The density of the oil = 1250 kg/m³. Reply
Answer:
1) The density of the object = 2500 kg/m³
2) The density of the oil = 1250 kg/m³
Explanation:
1) The information relating to the question are;
The mass of the object in air = 0.250 kgf
The mass of the object in water = 0.150 kgf
The mass of the object in the oil = 0.125 kgf
By Archimedes’s principle, we have;
The upthrust on the object in water = Mass in air – mass in water = The weight of the water displaced
The upthrust on the object in water = 0.250 – 0.150 = 0.1 kgf
∴ The weight of the water displaced = 0.1 kgf
Given that the object is completely immersed in the water, we have;
The volume of the water displaced = The volume of the object
The volume of 0.1 kg of water water displaced = Mass of the water/(Density of water)
The volume of 0.1 kg of water = 0.1/1000 = 0.0001 m³
The density of the object = (Mass in air)/ volume = 0.250/0.0001 = 2500 kg/m³
The density of the object = 2500 kg/m³
2) Whereby the mass of the object in the oil = 0.125 kgf
The upthrust of the oil = The weight of the oil displaced
The upthrust of the oil on the object = Mass of the object in air – mass of the object in the oil
The upthrust of the oil on the object = 0.250 – 0.125 = 0.125 kgf
The weight of the oil displaced = The upthrust of the oil
Given that the volume of the oil displaced = The volume of the oil, we have;
The volume of the oil displaced = 0.0001 m³
The mass of the 0.0001 m³ = 0.125 kg
Therefore the density of the oil = 0.125/0.0001 = 1250 kg/m³.
The density of the oil = 1250 kg/m³.