Share
An object undergoing simple harmonic motion takes 0.15 s to travel from one point of zero velocity to the next such point. The distance betw
Question
An object undergoing simple harmonic motion takes 0.15 s to travel from one point of zero velocity to the next such point. The distance between those points is 30 cm. (a) Calculate the period of the motion. s (b) Calculate the frequency of the motion. Hz (c) Calculate the amplitude of the motion. cm
in progress
0
Physics
1 year
2021-09-03T04:37:24+00:00
2021-09-03T04:37:24+00:00 1 Answers
7 views
0
Answers ( )
Answer:
Explanation:
Point of zero velocity are extreme points situated on either side of equilibrium position .
a )
Time taken to travel between these two points is .15 s
time for half the oscillation = .15 s
Time for full one oscillation = .30 s .
Time period of oscillation = .30 s
b)
frequency = 1 / time period
= 1 / .30s = 3.33 oscillation per second.
c )
Distance between these two point is equal to two times amplitude
2 x amplitude = 30 cm
amplitude = 15 cm