An object undergoing simple harmonic motion takes 0.15 s to travel from one point of zero velocity to the next such point. The distance betw

Question

An object undergoing simple harmonic motion takes 0.15 s to travel from one point of zero velocity to the next such point. The distance between those points is 30 cm. (a) Calculate the period of the motion. s (b) Calculate the frequency of the motion. Hz (c) Calculate the amplitude of the motion. cm

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Eirian 1 year 2021-09-03T04:37:24+00:00 1 Answers 7 views 0

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    2021-09-03T04:38:41+00:00

    Answer:

    Explanation:

    Point of zero velocity are extreme points situated on either side of equilibrium position .

    a )

    Time taken to travel between these two points is .15 s

    time for half the oscillation = .15 s

    Time for full one oscillation = .30 s .

    Time period of oscillation = .30 s

    b)

    frequency = 1 / time period

    = 1 / .30s = 3.33 oscillation per second.

    c )

    Distance between these two point is equal to two times amplitude

    2 x amplitude = 30 cm

    amplitude = 15 cm

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