An object of mass 10.0 kg is initially at rest. A 100 N force causes it to move horizontally througha distance of 6.00 m along a frictionles

Question

An object of mass 10.0 kg is initially at rest. A 100 N force causes it to move horizontally througha distance of 6.00 m along a frictionless surface. What is the change in the kinetic energy of thisobject?

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Khoii Minh 4 years 2021-07-26T16:18:03+00:00 2 Answers 68 views 0

Answers ( )

  1. Ben
    0
    2021-07-26T16:19:41+00:00
    Reply

    Answer:

    The change in the kinetic energy is 600 J

    Explanation:

    According the work energy expression, the change of kinetic energy is equal to the work done, the equation is:

    deltaE_{k} =W=Fs

    Where

    F = force = 100 N

    s = distance = 6 m

    Replacing:

    deltaE_{k} =100*6=600J

  2. Cherry
    0
    2021-07-26T16:19:58+00:00
    Reply

    Answer:

    Δ K.E = 600 J

    Explanation:

    Given that:

    the mass of the object = 10.0 kg

    Force = 100 N

    distance = 6.00 m

    what is the change in kinetic energy of this object = Δ K.E

    The expression for the change in the kinetic can be illustrated as follows:

    Δ K.E = W

    where W is the workdone on the object and is given by the formula :

    W = F × d

    So;

    Δ K.E = F × d

    Δ K.E = (100 N × 6.00 m)

    Δ K.E = 600 N.m

    Δ K.E = 600 J

    Therefore, the change in the kinetic energy of this object = 600 J

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