An object of mass 0.400.40 kg, hanging from a spring with a spring constant of 8.08.0 N/m, is set into an up-and-down simple harmonic motion

Question

An object of mass 0.400.40 kg, hanging from a spring with a spring constant of 8.08.0 N/m, is set into an up-and-down simple harmonic motion. What is the magnitude of the acceleration of the object when it is at its maximum displacement of 0.100.10 m

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Thái Dương 2 months 2021-07-28T16:14:33+00:00 1 Answers 4 views 0

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    2021-07-28T16:15:47+00:00

    Answer:

    Acceleration will be equal to 2m/sec^2      

    Explanation:

    We have given mass of the object m = 0.4 kg

    Spring constant k = 8 N/m

    Maximum displacement of the spring is given x = 0.1 m

    From newton’s law force is equal to F=ma…..eqn 1

    By hook’s law spring force is equal to F=kx …..eqn 2

    From equation 1 and equation 2

    ma=kx

    0.4\times a=8\times 0.1

    a=2m/sec^2

    So acceleration will be equal to 2m/sec^2

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