An object moving at a velocity of 32m/s slows to a stop in 4 seconds. What was its acceleration?

Question

An object moving at a velocity of 32m/s slows to a stop in 4 seconds. What was its acceleration?

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Linh Đan 6 months 2021-07-23T13:59:54+00:00 2 Answers 51 views 0

Answers ( )

    0
    2021-07-23T14:01:20+00:00

    Answer:

    8m/s

    Explanation:

    a=d/t

    a=32/4

    a=8 m/s

    0
    2021-07-23T14:01:33+00:00

    Answer:

    -8m/s^2

    Explanation:

    initial velocity(u)=32m/s

    Final velocity(v)=0

    Time(t)=4seconds

    Acceleration(a)=?

    v=u+axt

    0=32+ax4

    -32=4a

    a=-32/4

    a=-8m/s^2

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